下午在3203听张齐勋和郭文海老师的嵌入式软件开发与工具，因为各位同学都在进行开题报告，我就在最后一排拼命CAST
怎么也cast不过去，总是Unable to cast …. to …..
开始我用的接口文件是两个文件。就是原来的库从一个接口继承，然后新的cast强制转换为一个相同结构不同文件名的另一个接口！
IClass1 _instance = (IClass1)Activator.CreateInstance(System.Type.GetType("ClassLibrary1.Class1,ClassLibrary1"));
开始我这两个接口仅仅是命名空间不一样，无法cast
我想应该和命名空间没关系啊，然后我把命名空间改成一样的，还不行。
哦，我突然明白应该从同一个文件cast。
不过我还是不理解为什么完全一样的接口文件仅仅换了个地方就不能cast呢？？
于是我把正确的cast的方法写在下面，省得自己以后走冤枉路。
———————————————————————————————-
首先建立一个公用的接口
using System;
namespace ClassLibrary2
{
public interface IClass1
{
string printName();
}
}
然后从这个接口建类
using System;
using System.Collections.Generic;
using System.Text;
namespace ClassLibrary1
{
public class Class1 : ClassLibrary2.IClass1
{
public Class1()
{
}
public string printName()
{
return "s";
}
}
}
最后再cast的时候还从原来那个文件接口cast
ClassLibrary2.IClass1 _instance = (ClassLibrary2.IClass1)Activator.CreateInstance(System.Type.GetType("ClassLibrary1.Class1,ClassLibrary1"));
string s=_instance.printName();
Response.Write(s);
哦也
cast过来了
————
当当，下面打算研究
Activator.CreateInstance
与
Assembly.LoadFrom
的效率问题
————
当当，最近看了一部动画片叫做“斗牌传说”，不错，画风开始不喜欢，后来觉得，恩，也算可以了。
一部消遣的动画。还算可以吧。深度不够。
————
当当，最近看完了一部动画“蓝蓝岛漂流记”
这个很有意思
是我所认为的最好的画风之一
虽然情节很一般
————
当当，结束。怎么挣钱呢？
当当，有点晕
看不懂
高深哈…………..
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